(v^2+13v+38)/(v+7)=0

Solution for (v^2+13v+38)/(v+7)=0 equation:

(v^2+13v+38)/(v+7)=0


Domain of the equation: (v+7)!=0

We move all terms containing v to the left, all other terms to the right

v!=-7

v∈R


We multiply all the terms by the denominator


(v^2+13v+38)=0

We get rid of parentheses

v^2+13v+38=0

a = 1; b = 13; c = +38;
Δ = b2-4ac
Δ = 132-4·1·38
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{17}}{2*1}=\frac{-13-\sqrt{17}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{17}}{2*1}=\frac{-13+\sqrt{17}}{2}
$